document.write( "Question 984208: How can I determine the zeros roots and interceptors of this third-degree polynomial function f ( x ) = x ^ 3 + x ^ 2-4x \n" ); document.write( "
Algebra.Com's Answer #604992 by MathLover1(20850)\"\" \"About 
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first make \"f+%28+x+%29=0\"\r
\n" ); document.write( "\n" ); document.write( " \"0=+x%5E3+%2B+x%5E2-4x\"...factor out \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"0+=+x%28x%5E2%2Bx-4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"0+=+highlight%28x%29highlight%28%28x%5E2%2Bx-4%29%29\"... this product will be equal to zero only if one or both of the factors is equal to zero\r
\n" ); document.write( "\n" ); document.write( "so, one root is \"highlight%28x%5B1%5D=0%29\"\r
\n" ); document.write( "\n" ); document.write( "the other two roots we will get solving \"x%5E2%2Bx-4=0\"-use quadratic formula\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A1%2A%28-4%29+%29%29%2F%282%2A1%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1%2B16+%29%29%2F2+\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+17+%29%29%2F2+\" \r
\n" ); document.write( "\n" ); document.write( "exact solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x%5B2%5D+=+%28-1+%2B+sqrt%28+17+%29%29%2F2%29+\"
\n" ); document.write( "and
\n" ); document.write( "\"highlight%28x%5B3%5D+=+%28-1+-+sqrt%28+17+%29%29%2F2%29+\" \r
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