document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984208>Question 984208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can I determine the zeros roots and interceptors of this third-degree polynomial function f ( x ) = x ^ 3 + x ^ 2-4x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604991 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604991\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^3+x^2-4x=0 to find roots<BR>\n" );
document.write( "factor out x<BR>\n" );
document.write( "x(x^2+x-4)=0<BR>\n" );
document.write( "x=0 is one root<BR>\n" );
document.write( "x=(1/2)(-1+/- sqrt (1+16))  That works ;;;; sqrt 17=4.12<BR>\n" );
document.write( "x=1.56, -2.56\r<BR>\n" );
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document.write( "y intercept =0,0<BR>\n" );
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