document.write( "Question 984216: Pls u guys should help me out. The equation of a circle is given as x2 +y2-6x+8y-24=0. Find the equation of the diameter of the circle which passes through the point (-1,1) \n" ); document.write( "
Algebra.Com's Answer #604974 by josgarithmetic(39631)\"\" \"About 
You can put this solution on YOUR website!
Not a circle: x2 +y2-6x+8y-24=0\r
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\n" ); document.write( "\n" ); document.write( "This, a circle: x^2+y^2-6x+8y-24=0\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2-6x%2B8y-24=0\"
\n" ); document.write( "Complete the Square to put into standard form: \"%28x-3%29%5E2%2B%28y%2B4%29%5E2=49\".\r
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\n" ); document.write( "\n" ); document.write( "The diameter must include the center of the circle, (3,-4), and the given point (-1,1) must be on the LINE that contains a diameter of the circle (as asked).\r
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\n" ); document.write( "\n" ); document.write( "Same now as, find the equation for the line which passes through (3,-4) and (-1,1). Using point-slope form and only determining the slope of those two points, and choosing (-1,1), equation is \"highlight%28y-1=-%285%2F4%29%28x%2B1%29%29\".
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