document.write( "Question 83937: square root over -8
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Algebra.Com's Answer #60497 by praseenakos@yahoo.com(507)\"\" \"About 
You can put this solution on YOUR website!
Question:\r
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\n" ); document.write( "\n" ); document.write( "square root over -8
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\n" ); document.write( "\n" ); document.write( "The 'small' 3 infront of the squareroot means...you have to find out the cube root of \"-8%2F27\"\r
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\n" ); document.write( "\n" ); document.write( "-8 can be written as = -2 * -2 * -2 \r
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\n" ); document.write( "\n" ); document.write( "So cuberoot of -8 = -2 ( since you have to find our cuberoot, group factors of three.....here you have only one group.....take out one number from that group...that is -2)\r
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\n" ); document.write( "\n" ); document.write( "Similarly 27 can be written as 3* 3* 3\r
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\n" ); document.write( "\n" ); document.write( "And cuberoot of 27 = 3\r
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\n" ); document.write( "\n" ); document.write( "So \"cube+root+of+%28-8%2F27%29+\" = \"+-2%2F3+\"\r
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\n" ); document.write( "\n" ); document.write( "HOPE YOU FOUND THE EXPLANATION USEFUL....\r
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\n" ); document.write( "\n" ); document.write( "Praseena.\r
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