document.write( "Question 984192: the braking distance D in feet to stop a car traveling x miles per hour on dry, level pavement can be approximated by D=1/9x^2.
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\n" ); document.write( "(a)calculate the braking for 20 miles per hour and 70 miles per hour, how do your answers compare?
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\n" ); document.write( "(b) if the braking distance is 25 feet, estimate the speed of the car.
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\n" ); document.write( "(c) use the calculator to solve part (b) numerically. Do your answers agree?
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Algebra.Com's Answer #604966 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "(a)Calculate the braking for 20 miles per hour and 70 miles per hour, how do your answers compare?
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\n" ); document.write( "For 20 mph:
\n" ); document.write( "\"D=%281%2F9%29x%5E2\"
\n" ); document.write( "\"D=%281%2F9%29%2820mph%5E2%29\"
\n" ); document.write( "\"D=%281%2F9%29%28400%29=44.44ft\"
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\n" ); document.write( "For 70 mph:
\n" ); document.write( "\"D=%281%2F9%29%2870mph%29%5E2\"
\n" ); document.write( "\"D=%281%2F9%29%284900%29=544.44ft\"
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\n" ); document.write( "(c) Use the calculator to solve part (b) numerically. Do your answers agree?
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\n" ); document.write( "\"D=%281%2F9%29%28x%5E2%29\"
\n" ); document.write( "\"9D=x%5E2\"
\n" ); document.write( "\"3sqrt%28D%29=x\"
\n" ); document.write( "\"3sqrt%2825ft%29=x\"
\n" ); document.write( "\"15mph=x\"
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