document.write( "Question 984191: A committee has 25 members;15 whom are women and 10 men.
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Algebra.Com's Answer #604965 by Edwin McCravy(20055)\"\" \"About 
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document.write( "A committee has 25 members;15 whom are women and 10 men.\r\n" );
document.write( "-How many ways can a subcommittee of 8 be chosen to work on a project if\r\n" );
document.write( "*anyone of the committee be chosen?\r\n" );
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document.write( "(25 members, Choose 8) = 25C8 = 1081575\r\n" );
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document.write( "*at most 2 women can be chosen?\r\n" );
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document.write( "Three cases:\r\n" );
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document.write( "Case 1.  Choose no women at all.  (That's all men)\r\n" );
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document.write( "(10 men members, Choose 8) = 10C8 = 45\r\n" );
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document.write( "Case 2.  Choose 1 woman and 7 men. \r\n" );
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document.write( "(15 women, Choose 1)*(10 men, Choose 7) = 15C1*10C7 = 15*120 = 1800\r\n" );
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document.write( "Case 3.  Choose 2 woman and 6 men. \r\n" );
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document.write( "(15 women, Choose 2)*(10 men, Choose 6) = 15C2*10C6 = 105*210 = 22050\r\n" );
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document.write( "Grand total:  45 + 1800 + 22050 = 23895\r\n" );
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document.write( "Edwin
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