document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984168>Question 984168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Harry is 1/3 as old as Ron and 8 years younger than Hermoine, find the sum of their ages if Harry is 8 years old </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604946 by </B><A HREF=/tutors/aboutme.mpl?userid=satyareddy22><B>satyareddy22(84)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=satyareddy22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x,y,z be the ages of harry,ron and hermoine respectively.<BR>\n" );
document.write( "Harry is 1/3 as old as Ron<BR>\n" );
document.write( "=>x=y/3--------------(1)<BR>\n" );
document.write( "z-x=8----------------(2)<BR>\n" );
document.write( "Harry is 8 years old<BR>\n" );
document.write( "so, from (1) 8=y/3 =>y=24 yrs<BR>\n" );
document.write( "again from (2)z=8+x=8+8=16=>z=16yrs<BR>\n" );
document.write( "The sum of their ages = 8+16+24=48 yrs\r<BR>\n" );
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document.write( " </SPAN>\n" );
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