document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983954>Question 983954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jack invests $1000 at a certain annual interest rate, and he invests another $2000 at an annual rate that is one-half percent higher. If he receives a total of $190 interest in 1 year, at what rate is the $1000 invested? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604926 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> interest rate 1=x<BR>\n" );
document.write( "interest rate 2=0.005+x\r<BR>\n" );
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document.write( "(1000*x)+(2000)*(x+0.005)=190<BR>\n" );
document.write( "1000x+2000x+10=190<BR>\n" );
document.write( "3000x=180<BR>\n" );
document.write( "x=0.06 or 6%<BR>\n" );
document.write( "x+0.005=0.065 or 6.5%\r<BR>\n" );
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document.write( "1000*6%=$60 per year  ANSWER IS 6%<BR>\n" );
document.write( "2000*6.5%=$130per year<BR>\n" );
document.write( "$190 per year.<BR>\n" );
document.write( " </SPAN>\n" );
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