document.write( "Question 984118: If P is true, Q is false and R is true. Find the true value of the statement. ~[P➡(Q^R)] \n" ); document.write( "
Algebra.Com's Answer #604917 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A conditional is false whenever the antecedent is true and the consequent is nevertheless false. P, the antecedent, is true, but since Q is false, Q and R is false, the consequent is false and therefore the conditional is false.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The entire truth table for your statement is: \n" ); document.write( " \r\n" ); document.write( " P Q R Q&R P->(Q&R)\r\n" ); document.write( " T T T T T\r\n" ); document.write( " T T F F F\r\n" ); document.write( "* T F T F F\r\n" ); document.write( " T F F F F\r\n" ); document.write( " F T T T T\r\n" ); document.write( " F T F F T\r\n" ); document.write( " F F T F T\r\n" ); document.write( " F F F F T\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "The line with the asterisk is the given situation.\r \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it\r \n" ); document.write( "\n" ); document.write( " |