document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984097>Question 984097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Part A - A 28% w/v stock solution of NaCl is diluted with water according to a 1:8 ratio, and again with a 4:7 dilution ratio. Determine overall ratio.\r<BR>\n" );
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document.write( "I solved this as 1/14\r<BR>\n" );
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document.write( "Part B - If there is 84g of NaCl in the final diluted solution, determine the total amount of water added to the solution to perform the dilutions. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604895 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I agree, it is 1/14\r<BR>\n" );
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document.write( "If there are 84 grams with a 1:14 solution, it should be 2% of the whole amount, which is diluted to 4.2 liters, or 50 fold.  \r<BR>\n" );
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document.write( "84 grams is 28% of a solution of 300 cc.<BR>\n" );
document.write( "3.9 liters of water were added.<BR>\n" );
document.write( "The first batch was 2100, to make it 1:8<BR>\n" );
document.write( "The second batch was 1800, to reach 4200 cc or 4.2 liters.<BR>\n" );
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