document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=84037>Question 84037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am in need of help: how do you solve -4/y-3 + 1 = -10/y^2-y-12? Please help me! Thank you very much!  ( the problem is negative four divided by y minus three, plus one equals negative ten divided by y to the second power minus y minus twelve) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60489 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve -4/(y-3) + 1 = -10/(y^2-y-12)\r<BR>\n" );
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document.write( "Get a common denominator on the left side:\r<BR>\n" );
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document.write( "(-4+y-3)/(y-3) = -10/(y^2-y-12)\r<BR>\n" );
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document.write( "(y-7)/(y-3) = -10/(y^2-y-12)\r<BR>\n" );
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document.write( "Cross multiply to get:\r<BR>\n" );
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document.write( "(y-7)(y^2-y-12) = -10(y-3)\r<BR>\n" );
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document.write( "y^3-8y^2-5y+84 = -10y+30\r<BR>\n" );
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document.write( "y^3-8y^2+5y+54=0\r<BR>\n" );
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document.write( "I used a TI graphing calculator to find:\r<BR>\n" );
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document.write( "y=-2.08\r<BR>\n" );
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document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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