document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984006>Question 984006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a sports club has 48 members. One forth of them are girls. How many girls should become members of the club to have the girls to boys ratio to be 2:3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604795 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12 are girls, 36 are boys, and total is 48\r<BR>\n" );
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document.write( "For every girl added, the number changes by 12+x+36=48+x<BR>\n" );
document.write( "The ratio of girls to boys is (12+x)/36<BR>\n" );
document.write( "That has to be 2:3<BR>\n" );
document.write( "Cross multiply and 2*36=(12+x)*3<BR>\n" );
document.write( "72=36+3x<BR>\n" );
document.write( "36=3x<BR>\n" );
document.write( "x=12<BR>\n" );
document.write( "With 12 more girls, the ratio will be 24:36 (2:3), and there will be 60 members total.\r<BR>\n" );
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