document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983980>Question 983980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the z value to the left of the mean so that 82.12 % of the area under the distribution curve lies to the right of it.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604793 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 82.12% lies to the right then 100-82.12% lies to the left.<BR>\n" );
document.write( "Find the z score with a corresponding probability equal to 0.1788.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28z%29=0.1788 ALIGN=MIDDLE  ALT=\"P%28z%29=0.1788\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=z=-0.91995 ALIGN=MIDDLE  ALT=\"z=-0.91995\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );