document.write( "Question 983984: Hi
\n" ); document.write( "boxes a and b contain 112 pencils.when 1/5 of the pencils in box a were transfered to box b, both boxes contained the same number of pencils.
\n" ); document.write( "how many more pencils were there in box a than in box b at first.\r
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Algebra.Com's Answer #604783 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "Let  x  and  y  be the numbers of pencils in the boxes  a  and  b  respectively.\r
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\n" ); document.write( "\n" ); document.write( "Then you have two equations in two unknowns\r
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\n" ); document.write( "\n" ); document.write( "x + y = 112,               and\r
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\n" ); document.write( "\n" ); document.write( "x - \"1%2F5\"x = y + \"1%2F5\"x.\r
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\n" ); document.write( "\n" ); document.write( "From the second equation\r
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\n" ); document.write( "\n" ); document.write( "5x - x = 5y + x,     or\r
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\n" ); document.write( "\n" ); document.write( "3x = 5y.                 (1)\r
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\n" ); document.write( "\n" ); document.write( "From the first equation\r
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\n" ); document.write( "\n" ); document.write( "3x + 3y = 336.       (2)\r
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\n" ); document.write( "\n" ); document.write( "Now, replace  3x  in the equation  (2)  by  5y,  according to  (1).  You will get \r
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\n" ); document.write( "\n" ); document.write( "5y + 3y = 336,     or\r
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\n" ); document.write( "\n" ); document.write( "8y = 336,             or\r
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\n" ); document.write( "\n" ); document.write( "y = \"336%2F8\" = 42. \r
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\n" ); document.write( "\n" ); document.write( "Now,  x = \"5y%2F3\" = \"%285%2A42%29%2F3\" = \"210%2F3\" = \"70\".\r
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\n" ); document.write( "\n" ); document.write( "Hence,  there were  70  pencils in the box  a  and  42  pencils in the box  b.\r
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