document.write( "Question 983984: Hi
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document.write( "boxes a and b contain 112 pencils.when 1/5 of the pencils in box a were transfered to box b, both boxes contained the same number of pencils.
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document.write( "how many more pencils were there in box a than in box b at first.\r
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document.write( "THANK YOU \n" );
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Algebra.Com's Answer #604783 by ikleyn(52794)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x and y be the numbers of pencils in the boxes a and b respectively.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then you have two equations in two unknowns\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 112, and\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From the second equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x - x = 5y + x, or\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x = 5y. (1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From the first equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 3y = 336. (2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, replace 3x in the equation (2) by 5y, according to (1). You will get \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5y + 3y = 336, or\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8y = 336, or\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, x = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, there were 70 pencils in the box a and 42 pencils in the box b.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |