document.write( "Question 983977: how do i find the diagnol length of the rhombus which is inscribed in rectangle whose length is 16 cms and breadth is 12 cms. \n" ); document.write( "
Algebra.Com's Answer #604768 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
Here is my solution (EF = 15) to your problem using the diagram you sent me
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\n" ); document.write( "from snap shot rhombus AEDF gives us line segments AF, ED, AE, FD are
\n" ); document.write( "the same length
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\n" ); document.write( "AE^2 = CE^2 + AC^2 or
\n" ); document.write( "FD^2 = (16-FD)^2 + 12^2
\n" ); document.write( "FD^2 = 256 + FD^2 - 32FD + 244
\n" ); document.write( "32FD = 400
\n" ); document.write( "FD = 400 / 32 = 12.5
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\n" ); document.write( "area of rhombus(A) = FD * BD = 12.5 * 12 = 150
\n" ); document.write( "note that BD is height of rhombus
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\n" ); document.write( "also A = (1/2) * EF * AD
\n" ); document.write( "note AD^2 = AB^2 + BD^2 = 16^2 + 12^2 = 256 + 144 = 400
\n" ); document.write( "AD = square root(400) = 20
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\n" ); document.write( "(1/2) * EF * 20 = 150
\n" ); document.write( "10 * EF = 150
\n" ); document.write( "EF = 15
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