document.write( "Question 983903: Hi a and b had a total of 27 coins.when a gave 1/4 of his coins to b b had twice as many cojns as
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document.write( "a .b then found out that she had twice as many 20cent coins as 10 cent coins.how much money
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document.write( "did b have in the end.\r
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document.write( "thank you \n" );
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Algebra.Com's Answer #604734 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "You can find \n" ); document.write( "solving a system of equations, or by \n" ); document.write( "guess and check. \n" ); document.write( "From there, you can figure out how many coins b has in the end. \n" ); document.write( "Knowing how many coins b has in the end, \n" ); document.write( "and knowing that some of those coins are 10 cent coins, \n" ); document.write( "and the rest are 20 cent coins, \n" ); document.write( "with twice as many 20 cent coins as 10 cent coins, \n" ); document.write( "you can figure out how many coins of each kind b has in the end. \n" ); document.write( "Knowing how many coins of each kind b has in the end, you can figure out how much money those coins amount to.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "THE ALGEBRA WAY: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "a. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "THE \"GUESS-AND-CHECK\" WAY: \n" ); document.write( "Since a and b initially had a total of 27 coins, and a gave 1/4 of his coins to b, \n" ); document.write( "initially a must have had a number of coins that divides by 4 evenly, and is less than 27, \n" ); document.write( "such as 4, or 8, or 12, or 16, or 20, or 24. \n" ); document.write( "If it was 4, b would have initially had 27-4=23 coins; \n" ); document.write( "a would have given b just 1 coin, keeping the other 4-1=3 coins, \n" ); document.write( "and b would have had 23+3=26 coins in the end. \n" ); document.write( "Those 26 coins are a much greater number of coins than twice the 3 coins a had in the end. \n" ); document.write( "So, b must have started with less than 23 coins and a must have started with more than 4 coins. \n" ); document.write( "If a started with 8 coins, a would have given 2 of them to b, ending with 8-2=6 coins, \n" ); document.write( "while b would have started with 27-8=19 coins, and would have ended with 19+2=21. \n" ); document.write( "Those 21 coins are a greater number of coins than twice the 6 coins a had in the end. \n" ); document.write( "So, a must have started with more than 8 coins. \n" ); document.write( "If a started with 12 coins, a would have given 3 of them to b, ending with 12-3=9 coins, \n" ); document.write( "while b would have started with 27-12=15 coins, and would have ended with 15+3=18, \n" ); document.write( "which is twice as many coins as the 9 coins a ended up with. \n" ); document.write( "So, a started with 12 coins, and b had 18 coins in the end. \n" ); document.write( "Those 21 coins are a greater number of coins than twice the 6 coins a had in the end. \n" ); document.write( "From there you can continue as above, or guess-and-check to find how many of those 18 coins are 10 cent coins. \n" ); document.write( "If at the end just 1 of the coins b had was a 10-cent coin, b would have had 2 20-cent coins for a total of 1+2=3 coins. \n" ); document.write( "So the number of 10-cent coins must b had in the end must have been more than 1. \n" ); document.write( "If at the end just 5 of the coins b had were 10-cent coins, b would have had twice 5, or 10 20-cent coins for a total of 5+10=15 coins. \n" ); document.write( "Since b had 18 coins at the end, and 18 is more than 15, \n" ); document.write( "the number of 10-cent coins must b had in the end must have been more than 5. \n" ); document.write( "If at the end 6 of the coins b had were 10-cent coins, b would have had twice 6, or 12 20-cent coins for a total of 6+12=18 coins. \n" ); document.write( "Since b had 18 coins at the end, that is the mix of coins b had at the end, \n" ); document.write( "and 6 10-cent coins plus 12 20-cent coins make $3.00. \n" ); document.write( " \n" ); document.write( " |