document.write( "Question 83991: Please show me the way.. A restaurant determined that it's monthly cost function is given by C=3000=16q, where q is the number of dinners sold per month. q=1200-20p, where p is the price of the dinner.
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document.write( "a) Solve for p in terms of q and write the revenue and profit as a function of q
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document.write( "b) Find the break even point in terms of q. (the min and max # dinners/mo it can serve without losing $)
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document.write( "c) Write the cost, revenue and profit as functions of p and find breakeven points in terms of p.
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document.write( "d) Determin range of prices for which the restaurant make a profit.
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document.write( "I know this is alot, but I am lost. Any help is appreciated. \n" );
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Algebra.Com's Answer #60469 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A restaurant determined that it's monthly cost function is given by C=3000=16q, where q is the number of dinners sold per month. \n" ); document.write( "q = 1200-20p, where p is the price of the dinner. \n" ); document.write( ": \n" ); document.write( "a) Solve for p in terms of q and write the revenue and profit as a function of q \n" ); document.write( "q = 1200-20p \n" ); document.write( "+20p = 1200 - q \n" ); document.write( "p = \n" ); document.write( ": \n" ); document.write( "Revenue = p * q; substitute \n" ); document.write( "\n" ); document.write( "Rev = q( \n" ); document.write( " \n" ); document.write( "Rev = \n" ); document.write( "Rev = \n" ); document.write( ": \n" ); document.write( "Profit = Rev - Cost \n" ); document.write( ": \n" ); document.write( "Profit = (60q - .05q^2) - (3000 + 16q) \n" ); document.write( ": \n" ); document.write( "Profit = 60q - .05q^2 - 3000 - 16q \n" ); document.write( ": \n" ); document.write( "Profit = -.05q^2 + 44q - 3000 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "b) Find the break even point in terms of q. (the min and max # dinners/mo it can serve without losing $) \n" ); document.write( "Breakeven point is when profit = 0 \n" ); document.write( ": \n" ); document.write( "-.05q^2 + 44q - 3000 = 0 \n" ); document.write( ": \n" ); document.write( "Using the quadratic formula, I got: \n" ); document.write( "q ~ 75 meals min and q ~ 805 max, to not lose money \n" ); document.write( ": \n" ); document.write( "Graph this equation: \n" ); document.write( " \n" ); document.write( "Profit on the vertical and number of meals on the horizontal \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "c) Write the cost, revenue and profit as functions of p and find breakeven points in terms of p. \n" ); document.write( ": \n" ); document.write( "Cost = 3000 + 16q \n" ); document.write( "q = 1200-20p \n" ); document.write( "Replace q with (1200-20p) \n" ); document.write( "Cost = 3000 + 16(1200- 20p) \n" ); document.write( "Cost = 3000 + 19200 - 320p \n" ); document.write( "Cost = 22200 -320p \n" ); document.write( ": \n" ); document.write( "Revenue = p * q \n" ); document.write( "Replace q with (1200-20p) \n" ); document.write( "Rev = p(1200-20p) \n" ); document.write( "Rev = 1200p - 20p^2 \n" ); document.write( ": \n" ); document.write( "Profit = Revenue - Cost \n" ); document.write( "Profit = 1200p - 20p^2 - (22200 - 320p) \n" ); document.write( "Profit = 1200p - 20p^2 - 22200 + 320p \n" ); document.write( "Profit = -20p^2 + 1520p - 21000 \n" ); document.write( ": \n" ); document.write( "Breakeven is when profit = 0 \n" ); document.write( "-20p^2+ 1520p - 21000 = 0 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "d) Determine range of prices for which the restaurant make a profit. \n" ); document.write( ": \n" ); document.write( "Solve for p in the above equation: I got p = 18.93 and p = 57.85 \n" ); document.write( "Profit between these two values \n" ); document.write( "Graph would look like this: \n" ); document.write( " \n" ); document.write( "Profit on the vertical and meal price on the horizonal \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "A lot of chance for error here, check my calculations.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |