document.write( "Question 983456: I have two problems I urgently need assistance with. They are as follows:\r
\n" ); document.write( "\n" ); document.write( "1. A and B are independent events with P(A)=0.2 and P(B)=0.5. Calculate P(A or
\n" ); document.write( " B).\r
\n" ); document.write( "\n" ); document.write( "2. Consider events A and B with P(A\B)=3/4 P(A and B)=1/2
\n" ); document.write( " The probability of B is?\r
\n" ); document.write( "\n" ); document.write( "Regards,\r
\n" ); document.write( "\n" ); document.write( "Caroline
\n" ); document.write( "

Algebra.Com's Answer #604616 by Timnewman(323)\"\" \"About 
You can put this solution on YOUR website!
Hi Caro!
\n" ); document.write( "1.since A and B are independent event,there individual probabilities must be added.
\n" ); document.write( "Hence,
\n" ); document.write( " p(A or B)=p(A)+p(B)
\n" ); document.write( " From your question,
\n" ); document.write( " p(A)=0.2
\n" ); document.write( " p(B)=0.5
\n" ); document.write( "Therefore,
\n" ); document.write( " p(A or B)=0.2+0.5
\n" ); document.write( " =0.7
\n" ); document.write( "2.your second qestion involves conditional probability which states that,
\n" ); document.write( "
\n" ); document.write( "\"p%28A%2FB%29=p%28A%2AB%29%2F%28p%28B%29%29\"
\n" ); document.write( " if p(A/B)=3/4,
\n" ); document.write( " \"p%28A%2AB%29=1%2F2\"
\n" ); document.write( "\"p%28B%29=%281%2F2%29%2F%283%2F4%29\"
\n" ); document.write( "\"p%28B%29=%281%2F2%29%2A%284%2F3%29\"
\n" ); document.write( "\"p%28B%29=4%2F6\"
\n" ); document.write( "HOPE THIS HELPS;
\n" ); document.write( "------TIMNEWMAN------
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