document.write( "Question 983714: In 1990, the population of the U.S. was approximately 250 million and was expected to grow according to the function P(x)=250,000,000e^0.009x where x is the number of years after 1990. What will the expected U.S. population be in 2010, according to this model? \n" ); document.write( "
Algebra.Com's Answer #604602 by josgarithmetic(39630)\"\" \"About 
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The population in 1990 is a very big number with a bunch of digits. Give it a variable, \"Initial\" population, I.
\n" ); document.write( "You have implied x is time in years and growth constant is k=0.009. An economical way to solve the problem is to use all variables:
\n" ); document.write( "\"P=I%2Ae%5E%28kx%29\".\r
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\n" ); document.write( "\n" ); document.write( "Actually not much to solve; just you want to EVALUATE P when x=20, because 2010-1990=20. You would really keep most of the numbers in place.\r
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\n" ); document.write( "\n" ); document.write( "\"P%2820%29=250%2A10%5E6%2Ae%5E%280.009%2A20%29\".
\n" ); document.write( "A calculator would be easiest.
\n" ); document.write( "Here is available the calculator which comes with Windows o.s.
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\n" ); document.write( "0.18,[inv],[e^x],[=],[*],250,[=],... and then MULTIPLY BY 10^6.
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\n" ); document.write( "RESULT: 299000000
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