document.write( "Question 84008: x + y = -4
\n" ); document.write( "x - y = 2 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x + y = 10
\n" ); document.write( "y = x + 8 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3x + y = 5
\n" ); document.write( "4x - 7y = -10 \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "y - 2x = -5
\n" ); document.write( "3y - x = 5
\n" ); document.write( "

Algebra.Com's Answer #60460 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If you want to solve the system\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+-4\"
\n" ); document.write( "\"x+-+y+=+2\"\r
\n" ); document.write( "\n" ); document.write( "by addition/elimination, then...\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%2Ay=-4\"
\n" ); document.write( " \"1%2Ax-1%2Ay=2\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 1 and 1 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of 1 and 1 is 1, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -1 like this:
\n" ); document.write( "
\n" ); document.write( " \"1%2A%281%2Ax%2B1%2Ay%29=%28-4%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-1%2A%281%2Ax-1%2Ay%29=%282%29%2A-1\" Multiply the bottom equation (both sides) by -1
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"1%2Ax%2B1%2Ay=-4\"
\n" ); document.write( " \"-1%2Ax%2B1%2Ay=-2\"
\n" ); document.write( "
\n" ); document.write( " Notice how 1 and -1 add to zero (ie \"1%2B-1=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%281%2Ax-1%2Ax%29%2B%281%2Ay%2B1%2Ay%29=-4-2\"
\n" ); document.write( "
\n" ); document.write( " \"%281-1%29%2Ax%2B%281%2B1%29y=-4-2\"
\n" ); document.write( "
\n" ); document.write( " \"cross%281%2B-1%29%2Ax%2B%281%2B1%29%2Ay=-4-2\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"2%2Ay=-6\"
\n" ); document.write( "
\n" ); document.write( " \"y=-6%2F2\" Divide both sides by \"2\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-3\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"1%2Ax%2B1%2Ay=-4\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%28-3%29=-4\" Plug in \"y=-3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax-3=-4\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax=-4%2B3\" Subtract \"-3\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax=-1\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ax=%28-1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out \"1\" on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=-1\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=-1\", \"y=-3\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"-1\", \"-3\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%2Ay=-4\"
\n" ); document.write( " \"1%2Ax-1%2Ay=2\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"1%2Ax%2B1%2Ay=-4\" (red) \"1%2Ax-1%2Ay=2\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"-1\",\"-3\"). This verifies our answer.

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "Start with the given system
\n" ); document.write( "\"x+%2B+y+=+10\"
\n" ); document.write( "\"y+=+x+%2B+8+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+%2B+%28x%2B8%29+=+10\" Plug in y=x+8
\n" ); document.write( "\"2x%2B8+=+10\"
\n" ); document.write( "\"2x=+2\"
\n" ); document.write( "\"x=1\"\r
\n" ); document.write( "\n" ); document.write( "Now substitute x=1 into \"y=x%2B8\"
\n" ); document.write( "\"y+=+1+%2B+8+\"
\n" ); document.write( "\"y=9\"\r
\n" ); document.write( "\n" ); document.write( "So the solution is (1,9)\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "If you want to solve the system\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+y+=+5\"
\n" ); document.write( "\"4x+-+7y+=+-10\"\r
\n" ); document.write( "\n" ); document.write( "by addition/elimination, then...\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B1%2Ay=5\"
\n" ); document.write( " \"4%2Ax-7%2Ay=-10\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 3 and 4 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of 3 and 4 is 12, we need to multiply both sides of the top equation by 4 and multiply both sides of the bottom equation by -3 like this:
\n" ); document.write( "
\n" ); document.write( " \"4%2A%283%2Ax%2B1%2Ay%29=%285%29%2A4\" Multiply the top equation (both sides) by 4
\n" ); document.write( " \"-3%2A%284%2Ax-7%2Ay%29=%28-10%29%2A-3\" Multiply the bottom equation (both sides) by -3
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"12%2Ax%2B4%2Ay=20\"
\n" ); document.write( " \"-12%2Ax%2B21%2Ay=30\"
\n" ); document.write( "
\n" ); document.write( " Notice how 12 and -12 add to zero (ie \"12%2B-12=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2812%2Ax-12%2Ax%29%2B%284%2Ay%2B21%2Ay%29=20%2B30\"
\n" ); document.write( "
\n" ); document.write( " \"%2812-12%29%2Ax%2B%284%2B21%29y=20%2B30\"
\n" ); document.write( "
\n" ); document.write( " \"cross%2812%2B-12%29%2Ax%2B%284%2B21%29%2Ay=20%2B30\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"25%2Ay=50\"
\n" ); document.write( "
\n" ); document.write( " \"y=50%2F25\" Divide both sides by \"25\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=2\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"3%2Ax%2B1%2Ay=5\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B1%282%29=5\" Plug in \"y=2\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B2=5\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax=5-2\" Subtract \"2\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax=3\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F3%29%283%29%29%2Ax=%283%29%281%2F3%29\" Multiply both sides by \"1%2F3\". This will cancel out \"3\" on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=1\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=1\", \"y=2\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"1\", \"2\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B1%2Ay=5\"
\n" ); document.write( " \"4%2Ax-7%2Ay=-10\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"3%2Ax%2B1%2Ay=5\" (red) \"4%2Ax-7%2Ay=-10\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"1\",\"2\"). This verifies our answer.

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "If you want to solve the system\r
\n" ); document.write( "\n" ); document.write( "\"y+-+2x+=+-5\"
\n" ); document.write( "\"3y+-+x+=+5\"\r
\n" ); document.write( "\n" ); document.write( "by addition/elimination, then...\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ax%2B1%2Ay=-5\"
\n" ); document.write( " \"-1%2Ax%2B3%2Ay=5\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get -2 and -1 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of -2 and -1 is 2, we need to multiply both sides of the top equation by -1 and multiply both sides of the bottom equation by 2 like this:
\n" ); document.write( "
\n" ); document.write( " \"-1%2A%28-2%2Ax%2B1%2Ay%29=%28-5%29%2A-1\" Multiply the top equation (both sides) by -1
\n" ); document.write( " \"2%2A%28-1%2Ax%2B3%2Ay%29=%285%29%2A2\" Multiply the bottom equation (both sides) by 2
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"2%2Ax-1%2Ay=5\"
\n" ); document.write( " \"-2%2Ax%2B6%2Ay=10\"
\n" ); document.write( "
\n" ); document.write( " Notice how 2 and -2 add to zero (ie \"2%2B-2=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%282%2Ax-2%2Ax%29-1%2Ay%2B6%2Ay%29=5%2B10\"
\n" ); document.write( "
\n" ); document.write( " \"%282-2%29%2Ax-1%2B6%29y=5%2B10\"
\n" ); document.write( "
\n" ); document.write( " \"cross%282%2B-2%29%2Ax%2B%28-1%2B6%29%2Ay=5%2B10\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"5%2Ay=15\"
\n" ); document.write( "
\n" ); document.write( " \"y=15%2F5\" Divide both sides by \"5\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=3\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"-2%2Ax%2B1%2Ay=-5\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ax%2B1%283%29=-5\" Plug in \"y=3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ax%2B3=-5\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ax=-5-3\" Subtract \"3\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ax=-8\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F-2%29%28-2%29%29%2Ax=%28-8%29%281%2F-2%29\" Multiply both sides by \"1%2F-2\". This will cancel out \"-2\" on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=4\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=4\", \"y=3\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"4\", \"3\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ax%2B1%2Ay=-5\"
\n" ); document.write( " \"-1%2Ax%2B3%2Ay=5\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"-2%2Ax%2B1%2Ay=-5\" (red) \"-1%2Ax%2B3%2Ay=5\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"4\",\"3\"). This verifies our answer.

\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );