document.write( "Question 983686: A party of fishermen rented a boat for $240. Two of the men had to withdraw from the party and, as a result, the share of each of the others was increased by $10. How many fishermen were in the original party? \n" ); document.write( "
Algebra.Com's Answer #604595 by macston(5194)\"\" \"About 
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\n" ); document.write( "x=original number of fishermen
\n" ); document.write( ".
\n" ); document.write( "Original cost=$240/x
\n" ); document.write( "New cost=$240/(x-2)
\n" ); document.write( ".
\n" ); document.write( "New cost - original cost=$10
\n" ); document.write( "($240/(x-2))-$240/x=$10
\n" ); document.write( "$240x/(x-2)-$240=$10x
\n" ); document.write( "$240x-$240x+$480=$10x^2-$20x
\n" ); document.write( "$480=$10x^2-$20
\n" ); document.write( "48=x^2-2x
\n" ); document.write( "0=x^2-2x-48
\n" ); document.write( "0=(x-8)(x+6)
\n" ); document.write( "x-8=0 OR x+6=0
\n" ); document.write( "x=8 OR x=-6 There cannot be -6 fishermen, so:
\n" ); document.write( "ANSWER: The number of fishermen in the original party was 8.
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