document.write( "Question 983686: A party of fishermen rented a boat for $240. Two of the men had to withdraw from the party and, as a result, the share of each of the others was increased by $10. How many fishermen were in the original party? \n" ); document.write( "
Algebra.Com's Answer #604595 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "x=original number of fishermen \n" ); document.write( ". \n" ); document.write( "Original cost=$240/x \n" ); document.write( "New cost=$240/(x-2) \n" ); document.write( ". \n" ); document.write( "New cost - original cost=$10 \n" ); document.write( "($240/(x-2))-$240/x=$10 \n" ); document.write( "$240x/(x-2)-$240=$10x \n" ); document.write( "$240x-$240x+$480=$10x^2-$20x \n" ); document.write( "$480=$10x^2-$20 \n" ); document.write( "48=x^2-2x \n" ); document.write( "0=x^2-2x-48 \n" ); document.write( "0=(x-8)(x+6) \n" ); document.write( "x-8=0 OR x+6=0 \n" ); document.write( "x=8 OR x=-6 There cannot be -6 fishermen, so: \n" ); document.write( "ANSWER: The number of fishermen in the original party was 8. \n" ); document.write( " |