document.write( "Question 983780: (2x^2/3y^5)^-3 \n" ); document.write( "
Algebra.Com's Answer #604583 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(2x^2/3y^5)^-3
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\n" ); document.write( "The negative in the exponent means \"invert\"
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\n" ); document.write( "So you get:
\n" ); document.write( "= [(3y^5)/(2x^2)]^3
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\n" ); document.write( "= [27y^15/8x^6]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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