document.write( "Question 983780: (2x^2/3y^5)^-3 \n" ); document.write( "
Algebra.Com's Answer #604583 by stanbon(75887) ![]() You can put this solution on YOUR website! (2x^2/3y^5)^-3 \n" ); document.write( "----- \n" ); document.write( "The negative in the exponent means \"invert\" \n" ); document.write( "----- \n" ); document.write( "So you get: \n" ); document.write( "= [(3y^5)/(2x^2)]^3 \n" ); document.write( "-------- \n" ); document.write( "= [27y^15/8x^6] \n" ); document.write( "--------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |