document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83999>Question 83999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried this problem and cannot seem to get an answer for it!  Please help me!!!  Here it is:\r<BR>\n" );
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document.write( "A garden with an area of 105 square meters is surrounded by a sidewalk of uniform width.  The sidewalk and garden together are 19 meters long and 11 meters wide.  How wide is the sidewalk?\r<BR>\n" );
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document.write( "A: 1 meter  B: 2 meters  C: 1.5 meters  D: 0.5 meters\r<BR>\n" );
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document.write( "I did:<BR>\n" );
document.write( "19 x 11 = 209<BR>\n" );
document.write( "209-105 = 104<BR>\n" );
document.write( "... I don't know what to do from there!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60455 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you're kind of on the right track ... let x be the width of the sidewalk\r<BR>\n" );
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document.write( "the dimensions of the garden are the overall dimensions minus twice the width of the sidewalk\r<BR>\n" );
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document.write( "area=(length)(width) ... 105=(19-2x)(11-2x) ... 105=209-60x+4x^2 ... 0=104-60x+4x^2\r<BR>\n" );
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document.write( "x^2-15x+26=0 ... (x-13)(x-2)=0 ... x=13, x=2 ... the 13 is not a realistic solution (overall width is only 11) </SPAN>\n" );
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