document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983743>Question 983743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove that the sum of all angles of a triangle is 180'. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604531 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> draw a line parallel to the base of your triangle, note that the other two sides of the triangle are transversal's intersecting the base and the parallel line which touches the top of the triangle.  Since alternate angles of a transversal are equal, angles A+B+C = 180 degrees<BR>\n" );
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