document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983717>Question 983717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume ABC is a right triangle with the right angle at C.<BR>\n" );
document.write( "If A= 36º30' and b= 43.5cm, find c.<BR>\n" );
document.write( "(Round your answer to the nearest tenth of a cm.)\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604510 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> note that A = 36 degrees 30 minutes = 36.5 degrees, then<BR>\n" );
document.write( "cos(36.5) = 43.5 / c<BR>\n" );
document.write( "c = 43.5 / cos(36.5) = 54.114111767, therefore<BR>\n" );
document.write( "c = 54.1 cm<BR>\n" );
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