document.write( "Question 983692: Solve by completing the square and quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "1.) x^2-6x+8=0
\n" ); document.write( "2.)t^2=4-3t \n" ); document.write( "

Algebra.Com's Answer #604506 by mananth(16946) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "x^2-6x+8=0\r
\n" ); document.write( "\n" ); document.write( "x^2-6x = -8\r
\n" ); document.write( "\n" ); document.write( "x^2-6x+9= +9-8\r
\n" ); document.write( "\n" ); document.write( "(x-3)^2= 1\r
\n" ); document.write( "\n" ); document.write( "take the square root\r
\n" ); document.write( "\n" ); document.write( "(x-3) = +/-1\r
\n" ); document.write( "\n" ); document.write( "x=4 OR 2\r
\n" ); document.write( "\n" ); document.write( "t^2=4-3t\r
\n" ); document.write( "\n" ); document.write( "t^2+3t =4\r
\n" ); document.write( "\n" ); document.write( "Third term = ((1/2) the co-efficient of second term)^2\r
\n" ); document.write( "\n" ); document.write( "t^2+3t + 9/4 = 4+9/4\r
\n" ); document.write( "\n" ); document.write( "(t+ 3/2)^2= 25/4\r
\n" ); document.write( "\n" ); document.write( "t+ 3/2 = +/- 5/2\r
\n" ); document.write( "\n" ); document.write( "t = -3/2 + 4/2 OR -3/2 -5/2\r
\n" ); document.write( "\n" ); document.write( "t= 1/2 OR -4\r
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