document.write( "Question 983553: During one year in a school,0.625 of the student had measles,0.5 had chickenpox and 0.125 had neither. What fraction of the school had both measles and chickenpox? \n" ); document.write( "

Algebra.Com's Answer #604490 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "If 12.5% had neither, then 87.5% had one or the other or both. The percentage that ONLY had measles is then 67.5% -

is the percentage that had both. And the percentage that ONLY had chicken pox is 50% -

. Then the 87.5% is comprised of the number that only had measles, the number that only had chicken pox and the number that had both:\r
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\n" ); document.write( "\n" ); document.write( "Solve for

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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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