document.write( "Question 983571: A person covers a certain distance on car. Had he moved 30 km/hr faster, he would have taken 2.5 hrs less. If he has moved 10 km h slower, he would have taken 2.5hrs more. What is his original speed. \n" ); document.write( "
Algebra.Com's Answer #604484 by josgarithmetic(39799)\"\" \"About 
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document.write( "                speed        time       distance    EQUATIONS\r\n" );
document.write( "NORMAL           r            t          d          rt=d\r\n" );
document.write( "FASTER          r+30         t-2.5       d          (r+30)(t-2.5)=d\r\n" );
document.write( "SLOWER          r-10         t+2.5       d          (r-10)(t+2.5)=d\r\n" );
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document.write( "Additional equation might help:          (r+30)(t-2.5)=(r-10)(t+2.5)\r\n" );
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\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "FAST equation
\n" ); document.write( "\"rt%2B30t-2.5r-75=d\"
\n" ); document.write( "\"d%2B30t-2.5r-75=d\"
\n" ); document.write( "\"30t-2.5r-75=0\"
\n" ); document.write( "-
\n" ); document.write( "SLOW equation
\n" ); document.write( "\"rt-10t%2B2.5r-25=d\"
\n" ); document.write( "\"-10t%2B2.5r-25=0\"
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\n" ); document.write( "The additional equation in the table is not necessary.\r
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\n" ); document.write( "\n" ); document.write( "The equations as found can be simplified for convenience if multiply each by 2.
\n" ); document.write( "Those as a system of equations:
\n" ); document.write( "\"system%2860t-5r-150=0%2C-20t%2B5r-50=0%29\"
\n" ); document.write( "and then further
\n" ); document.write( "\"system%2812t-r-30=0%2C4t-r%2B10=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "Elimination Method is perfectly convenient for the system.
\n" ); document.write( "\"12t-r-30-%284r-r%2B10%29=0-0\"
\n" ); document.write( "\"8r-30-10=0\"
\n" ); document.write( "\"8r=40\"
\n" ); document.write( "\"highlight%28highlight%28r=5%29%29\"
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