document.write( "Question 983667: Hi, I have to solve the following equation:\r
\n" ); document.write( "\n" ); document.write( "3/x+ 5/x+2 = 2 \r
\n" ); document.write( "\n" ); document.write( "^ Ive had trouble searching information on these types of equations because in the 5/x+2 part the '2' is actually in the denominator, not beside the fraction, but all search engines pick it as being to the right.\r
\n" ); document.write( "\n" ); document.write( "What I tried was multiplying both sides by x to get 3+5/2= 2 and then solving it, but I don't think I'm allowed to cancel out the x from x+2 in this way. Any help would be much appreciated.
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Algebra.Com's Answer #604468 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Is this the problem:
\n" ); document.write( "\"+3%2Fx+%2B+5%2F%28+x%2B2+%29+=+2+\"
\n" ); document.write( "If so, multiply both sides by \"+x%2A%28+x%2B2+%29+\"
\n" ); document.write( "\"+3%2A%28+x%2B2+%29+%2B+5x+=+2x%2A%28+x%2B2+%29+\"
\n" ); document.write( "\"+3x+%2B+6+%2B+5x+=+2x%5E2+%2B+4x+\"
\n" ); document.write( "\"+2x%5E2+%2B+4x+-+3x+-+5x+-+6+=+0+\"
\n" ); document.write( "\"+2x%5E2+-+4x+-+6+=+0+\"
\n" ); document.write( "Divide both sides by \"+2+\"
\n" ); document.write( "\"+x%5E2+-+2x+-+3+=+0+\"
\n" ); document.write( "By looking at this, I see the solution is:
\n" ); document.write( "\"+%28+x+-3+%29%2A%28+x+%2B+1+%29+=+0+\"
\n" ); document.write( "\"+x+=+3+\"
\n" ); document.write( "\"+x+=+-1+\"
\n" ); document.write( "--------------
\n" ); document.write( "Check solutions by plugging them back into
\n" ); document.write( "the original problem
\n" ); document.write( "\"+3%2Fx+%2B+5%2F%28+x%2B2+%29+=+2+\"
\n" ); document.write( "\"+3%2F3+%2B+5%2F%28+3%2B2+%29+=+2+\"
\n" ); document.write( "\"+1+%2B+1+=+2+\"
\n" ); document.write( "OK
\n" ); document.write( "\"+3%2Fx+%2B+5%2F%28+x%2B2+%29+=+2+\"
\n" ); document.write( "\"+3%2F-1+%2B+5%2F%28+-1%2B2+%29+=+2+\"
\n" ); document.write( "\"+-3+%2B+5%2F1+=+2+\"
\n" ); document.write( "\"+-3+%2B+5+=+2+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );