document.write( "Question 983594: Let U={1,2,3,4,5,6,7,8,9,10}
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document.write( "Let A={1,2,4,6,9,3}
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document.write( "Let B={1,3,4,5,8}
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document.write( "Let C={4,5,9,3}\r
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document.write( "How to determine C-A' \n" );
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Algebra.Com's Answer #604442 by MathLover1(20855) You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "A' --> complement of subset A --> all elements in \n" ); document.write( "\n" ); document.write( "if \n" ); document.write( "U={1,2,3,4,5,6,7,8,9,10} and \n" ); document.write( "A={1,2,4,6,9,3}\r \n" ); document.write( "\n" ); document.write( "then \n" ); document.write( "A' = {5,7,8,10}\r \n" ); document.write( "\n" ); document.write( "if C={4,5,9,3} and A' = {5,7,8,10}, then C-A' is:\r \n" ); document.write( "\n" ); document.write( "by def: The difference or relative compliment of two sets C and A', denoted by \n" ); document.write( "C-A' is the set of all elements in C that are not in A'.\r \n" ); document.write( "\n" ); document.write( " as you can see, none of elements in C are in A',so \n" ); document.write( "C-A'={4,5,9,3}=C\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |