document.write( "Question 983647: The perimeter of a rectangular building is 170 meters. The area is 1,624 square meters. What are the dimensions of the building? \n" ); document.write( "
Algebra.Com's Answer #604422 by Timnewman(323)![]() ![]() You can put this solution on YOUR website! hi, \n" ); document.write( "Let L and w be the lenght and the width \n" ); document.write( "if perimeter P of the bulding is 170m,therefore, \n" ); document.write( "2(L+w)=170 \n" ); document.write( "then, \n" ); document.write( "L+w=85----(1) \n" ); document.write( "also, if the area is 1624m²,therefore, \n" ); document.write( " L*w=1624----(2) \n" ); document.write( "from (1) \n" ); document.write( "L=85-w----(3) \n" ); document.write( "put (3) in (2) \n" ); document.write( "(85-w)w=1624 \n" ); document.write( "85w-w²=1624 \n" ); document.write( "w² -85w+1624=0 \n" ); document.write( "factorize the equation formed above and get; \n" ); document.write( "(w-29)(w-56)=0 \n" ); document.write( "w=29 or w=56 \n" ); document.write( "put w=29 in (3) \n" ); document.write( "L=85-29 \n" ); document.write( "L=56 \n" ); document.write( "put w=56 in (3) \n" ); document.write( "L=85-56 \n" ); document.write( "L=29 \n" ); document.write( "From the above,the lenght L of the bulding is 56m and the width is 29m. \n" ); document.write( " HOPE THIS HELPS;... \n" ); document.write( "-------TIMNEWMAN------ \n" ); document.write( " \n" ); document.write( " |