document.write( "Question 983647: The perimeter of a rectangular building is 170 meters. The area is 1,624 square meters. What are the dimensions of the building? \n" ); document.write( "
Algebra.Com's Answer #604422 by Timnewman(323)\"\" \"About 
You can put this solution on YOUR website!
hi,
\n" ); document.write( "Let L and w be the lenght and the width
\n" ); document.write( "if perimeter P of the bulding is 170m,therefore,
\n" ); document.write( "2(L+w)=170
\n" ); document.write( "then,
\n" ); document.write( "L+w=85----(1)
\n" ); document.write( "also, if the area is 1624m²,therefore,
\n" ); document.write( " L*w=1624----(2)
\n" ); document.write( "from (1)
\n" ); document.write( "L=85-w----(3)
\n" ); document.write( "put (3) in (2)
\n" ); document.write( "(85-w)w=1624
\n" ); document.write( "85w-w²=1624
\n" ); document.write( "w² -85w+1624=0
\n" ); document.write( "factorize the equation formed above and get;
\n" ); document.write( "(w-29)(w-56)=0
\n" ); document.write( "w=29 or w=56
\n" ); document.write( "put w=29 in (3)
\n" ); document.write( "L=85-29
\n" ); document.write( "L=56
\n" ); document.write( "put w=56 in (3)
\n" ); document.write( "L=85-56
\n" ); document.write( "L=29
\n" ); document.write( "From the above,the lenght L of the bulding is 56m and the width is 29m.
\n" ); document.write( " HOPE THIS HELPS;...
\n" ); document.write( "-------TIMNEWMAN------
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