document.write( "Question 983632: Please help me solve this equation ... Find the value of x satisfying ...\"2%5E%283x%2B1%29-3.2%5E%28x%29%2B2%5E%28x%2B1%29=2%5Ex\" \n" ); document.write( "
Algebra.Com's Answer #604405 by ikleyn(52810)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let us introduce a new variable.\r
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\n" ); document.write( "\n" ); document.write( "Let  y  be  \"2%5Ex\":   \"y\" = \"2%5Ex\". \r
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\n" ); document.write( "\n" ); document.write( "Then you can re-write your equation in the form\r
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\n" ); document.write( "\n" ); document.write( "\"2y%5E3\" - \"3y\" + \"2y\" = \"y\".\r
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\n" ); document.write( "\n" ); document.write( "Collect common terms:\r
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\n" ); document.write( "\n" ); document.write( "\"2y%5E3\" = \"2y\".\r
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\n" ); document.write( "\n" ); document.write( "Since  \"y\" = \"2%5Ex\"  can not be zero,  you can divide both sides by  \"2y\",  and you will get \r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2\" = \"1\".\r
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\n" ); document.write( "\n" ); document.write( "It implies  \"y\" = \"1\".\r
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\n" ); document.write( "\n" ); document.write( "Hence,  \"2%5Ex\" = \"1\". \r
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\n" ); document.write( "\n" ); document.write( "Therefore,  x = 0. \r
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\n" ); document.write( "\n" ); document.write( "Answer.  x = 0.\r
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