document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983614>Question 983614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm shorter than the diagonal. The length is 2 cm longer than twice the width. Find the perimeter of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604388 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=width<BR>\n" );
document.write( "2x+2=length<BR>\n" );
document.write( "diagonal is the hypotenuse of a right triangle<BR>\n" );
document.write( "x^2+(4x^2+8x+4)=(2x+3)^2.  I squared the width and length and set them equal to the diagonal's length squared\r<BR>\n" );
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document.write( "5x^2+8x+4=4x^2+12x+9<BR>\n" );
document.write( "x^2+-4x-5=0<BR>\n" );
document.write( "(x-5)(x+1)=0<BR>\n" );
document.write( "x=5, only reasonable solution.<BR>\n" );
document.write( "Width is 5, length is 12, diagonal length is 13 (5-12-13 right triangle)<BR>\n" );
document.write( "perimeter is 2 width (10) + 2 length (24)=34 cm. </SPAN>\n" );
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