document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983562>Question 983562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!\r<BR>\n" );
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document.write( "I have been struggling with this question.\r<BR>\n" );
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document.write( "It is :\r<BR>\n" );
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document.write( "Completely factor x^3-3x^2-6x+8 and then set it to zero and solve for x.\r<BR>\n" );
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document.write( "Thank you so much for your help.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604342 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39625)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the roots of the polynomial.  Use synthetic division to test the roots,  -1,-2,-4,-8,1,2,4,8.  You should find remainders to be 0 when you test for -2, or 1, or 4.  Finding any one of these through synthetic division gives a resulting quadratic factor as the quotient, easily solved through factoring.\r<BR>\n" );
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