document.write( "Question 983517: Hello, I am having trouble understanding and solving this problem:\r
\n" ); document.write( "\n" ); document.write( "A kayaker can paddle 12 miles in 2 hours moving with the river current. Paddling at the same pace, the trip back against the current takes 4 hours. Assume that the river current is constant. Find what the kayaker's speed would be in still water.\r
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Algebra.Com's Answer #604310 by MathTherapy(10552)\"\" \"About 
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Hello, I am having trouble understanding and solving this problem:\r
\n" ); document.write( "\n" ); document.write( "A kayaker can paddle 12 miles in 2 hours moving with the river current. Paddling at the same pace, the trip back against the current takes 4 hours. Assume that the river current is constant. Find what the kayaker's speed would be in still water.\r
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\n" ); document.write( "\n" ); document.write( "-Thank you.
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Let speed of kayak, in still water be S, and speed of current, C
\n" ); document.write( "Total speed moving with the current: \"12%2F2\", or 6 mph
\n" ); document.write( "Total speed moving against the current: \"12%2F4\", or 3 mph
\n" ); document.write( "We then get: S + C = 6 ------- eq (i)
\n" ); document.write( " S - C = 3 ------- eq (ii)
\n" ); document.write( " 2S = 9 ------- Adding eqs (ii) & (i)
\n" ); document.write( "S, or speed in still water = \"9%2F2\", or \"highlight_green%284.5%29\" mph \n" ); document.write( "
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