document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83969>Question 83969</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rewrite the middle term as the sum of two terms and then factor completely.<BR>\n" );
document.write( "	15x^2 – 21x + 6<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60431 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15x^2 – 21x + 6<BR>\n" );
document.write( "Leading Coefficient * Constant<BR>\n" );
document.write( "15 * 6 = 90<BR>\n" );
document.write( "Factors of 90 that Sum to -21 ?<BR>\n" );
document.write( "-15 and - 6<BR>\n" );
document.write( "15x^2 - 15x - 6x + 6<BR>\n" );
document.write( "(15x^2 - 15x) + (-6x + 6)<BR>\n" );
document.write( "15x(x - 1) - 6(x - 1)<BR>\n" );
document.write( "(15x - 6)(x - 1) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );