document.write( "Question 983474: Hi
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document.write( "there were 1518 boys and girls in a hall.when 2/3 of the boys and 1/5 of the girls left there were
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document.write( "twice as many girls as boys remaining. \r
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document.write( "How many girls were there at the beginning
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document.write( "how many boys were there at the beginning\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #604300 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let g = original no. of girls \n" ); document.write( "let b = original no. of boys \n" ); document.write( ": \n" ); document.write( "there were 1518 boys and girls in a hall. \n" ); document.write( "g + b = 1518 \n" ); document.write( "when 2/3 of the boys and 1/5 of the girls left there were twice as many girls as boys remaining. \n" ); document.write( "That means that 4/5 of the girls and 1/3 of the boys remained, so we can say \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply by 15 to get rid of the denominators \n" ); document.write( "3(4g) = 5(2b) \n" ); document.write( "12g = 10b \n" ); document.write( "Simplify divide by 2 \n" ); document.write( "6g = 5b \n" ); document.write( "b = \n" ); document.write( "b = 1.2 g \n" ); document.write( "in the 1st equation replace b with 1.2g \n" ); document.write( "g + 1.2g = 1518 \n" ); document.write( "2.2g = 1518 \n" ); document.write( "g = 1518/2.2 \n" ); document.write( "g = 690 girls originally \n" ); document.write( "then \n" ); document.write( "1518 - 690 = 828 boys originally \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, by finding the remaining girls and boys \n" ); document.write( "1/3 * 828 = 276 boys remain \n" ); document.write( "4/5 * 690 = 552 girls \n" ); document.write( "2 * 276 = 552 twice as many girls as boys \n" ); document.write( " \n" ); document.write( " |