document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983453>Question 983453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sara opens a bank account with $200. The account accrues 2% interest compounded annually.\r<BR>\n" );
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document.write( "How much money, to the nearest cent, will she have in her account at the end of 3 years? (Use the formula A=P(1+rn)nt, where P= initial amount of money, r = interest rate, t = the number of years, and n = number of times the interest is compounded per year.)\r<BR>\n" );
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document.write( "$\r<BR>\n" );
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document.write( "Enter a number like 157.23.<BR>\n" );
document.write( "Part 2\r<BR>\n" );
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document.write( "Sara wants to calculate the amount she will earn between year 3 and year 5.\r<BR>\n" );
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document.write( "How much interest will Sara earn during this time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604253 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=po(1+r/n)^nt<BR>\n" );
document.write( "=200(1.02)^3=200*(1.0612)=212.24 (round only at the end)\r<BR>\n" );
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document.write( "I have year 3, and now I need year 5.\r<BR>\n" );
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document.write( "=200(1.02)^5=200*1.1040=220.82.  Again, I rounded here, but the answer is on the calculator, and I don't round until the end.  That is why the 0.82 is there.\r<BR>\n" );
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document.write( "That isn't the answer.<BR>\n" );
document.write( "The amount between years 3 and 5 is $8.58. </SPAN>\n" );
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