document.write( "Question 83955: Demand equation. Helen’s Health food usually sells 400 cans of Propac Muscle Punch per week when the price is $5 per can. After experimenting with the weekly demand can be found by using the equation d=600-40p where d is the number of cans and p is the price per can.
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document.write( "a) will Helen sell more or less Muscle Punch if she raises her price from $5?
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document.write( "b) What happens to her sales every time she raises her price by $1?
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document.write( "c) Graph the equation
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document.write( "d) What is the maximum price that she can charge and still sell at least one can?
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Algebra.Com's Answer #60421 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! d = 600 - 40p where d is the number of cans and p is the price per can \n" ); document.write( "a) will Helen sell more or less Muscle Punch if she raises her price from $5? \n" ); document.write( "when p = 5 ~> d = 400 \n" ); document.write( "when p + 1 = 6 ~> d = 360 Less \n" ); document.write( "b) What happens to her sales every time she raises her price by $1? \n" ); document.write( "p = 5 ~> d = 400 \n" ); document.write( "p = 6 ~> d = 360 (-40) \n" ); document.write( "p = 7 ~> d = 320 (-40) \n" ); document.write( "Decreases 40 each time ... \n" ); document.write( "c) Graph the equation \n" ); document.write( "p is represented by the x-axis \n" ); document.write( "d is represented by the y-axis \n" ); document.write( " \n" ); document.write( "d) What is the maximum price that she can charge and still sell at least one can? \n" ); document.write( "1 =< 600 - 40p \n" ); document.write( "-599 =< - 40p \n" ); document.write( "599 => 40p \n" ); document.write( "14.975 => p \n" ); document.write( " \n" ); document.write( " |