document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983226>Question 983226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the figure above, OP Is a radius of the circle, PX is a tangent of the circle at point P, and the area of triangle OPX is 12. What is the area of the circle? \r<BR>\n" );
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document.write( "a. 16Pi<BR>\n" );
document.write( "b. 12Pi<BR>\n" );
document.write( "c. 18Pi<BR>\n" );
document.write( "d. 24Pi\r<BR>\n" );
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document.write( "http://152.46.13.240/MoodleContent/SATprep/Math%20Unit%207/Lesson%203%20Assignment/cb2.gif </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604174 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(53751)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "The triangle &nbsp;<B>OPX</B>&nbsp; is right-angled triangle because the radius drawn to the tangent point is perpendicular to the tangent. \r<BR>\n" );
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document.write( "Therefore the area of the triangle  &nbsp;<B>OPX</B>&nbsp; is half-product of its legs &nbsp;<B>OP</B>&nbsp; and &nbsp;<B>PX</B>:\r<BR>\n" );
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document.write( "S = 12 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.|<B>OP</B>|.|<B>OP</B>| = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >*|<B>OP</B>|*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6 ALIGN=MIDDLE  ALT=\"6\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 3*|<B>OP</B>|.\r<BR>\n" );
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document.write( "It gives for the radius of the circle &nbsp;&nbsp;r = |<B>OP</B>| = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2F3 ALIGN=MIDDLE  ALT=\"12%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 4.\r<BR>\n" );
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document.write( "Hence, &nbsp;the area of the circle is &nbsp;<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A4%5E2 ALIGN=MIDDLE  ALT=\"pi%2A4%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16pi ALIGN=MIDDLE  ALT=\"16pi\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "<B>Answer</B>. &nbsp;The area of the circle is &nbsp;<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16pi ALIGN=MIDDLE  ALT=\"16pi\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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