document.write( "Question 983388: The area of the rectangle is represented by 5x^2 + 19x + 12. What is the length?
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document.write( "Width=5x + 4
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Algebra.Com's Answer #604162 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Notice how the last term of 5x^2 + 19x + 12 is 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The constant term of 5x+4 is 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide: 12/4 = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the constant term in the length must be 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The first term in the area expression is 5x^2. The first term in the width is 5x. Divide: 5x^2 over 5x = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the variable term must be just x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The length is (x+3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+3)*(5x+4) = 5x^2 + 19x + 12 \n" ); document.write( " |