document.write( "Question 983385: If the sides of a square are decreased by 3 cm, the area is decreased by 81 cm^2. What were the dimensions of the original square?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #604159 by macston(5194) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "S=side of original square
\n" ); document.write( " $\"%28S-3cm%29%5E2=S%5E2-81\"$
\n" ); document.write( " $\"S%5E2-6S%2B9=S%5E2-81\"$
\n" ); document.write( " $\"-6S%2B9=-81\"$
\n" ); document.write( " $\"90=6S\"$
\n" ); document.write( " $\"15=S\"$ ANSWER: Sides of the original square were 15 cm.
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "Original Area=S^2=(15cm)^2=225cm^2
\n" ); document.write( "New area=(S-3cm)^2=15cm-3cm)^2=(12cm)^2=144cm^2
\n" ); document.write( "Original area-New area=81cm^2
\n" ); document.write( "225cm^2-144cm^2=81cm^2
\n" ); document.write( "81cm^2=81cm^2 \n" ); document.write( "

\n" );