document.write( "Question 983298: If 5*3=4
\n" ); document.write( " 2*8=2
\n" ); document.write( " 5*1=6
\n" ); document.write( " 6*3=3
\n" ); document.write( "Find the value of
\n" ); document.write( " 1*7=? \n" ); document.write( "

Algebra.Com's Answer #604143 by MathLover1(20850) $\"\"$ $\"About$

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$\"9\"$ is the answer\r
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\n" ); document.write( " $\"+5%2A3=4\"$
\n" ); document.write( " $\"2%2A8=2\"$
\n" ); document.write( " $\"5%2A1=6\"$
\n" ); document.write( " $\"+6%2A3=3\"$
\n" ); document.write( " $\"1%2A7=9\"$ \r
\n" ); document.write( "\n" ); document.write( " because in the first one it equals $\"4\"$ \r
\n" ); document.write( "\n" ); document.write( " the second sum equals $\"2\"$
\n" ); document.write( " the third sum is $\"6\"$ which is $\"4+%2B+2\"$ \r
\n" ); document.write( "\n" ); document.write( " the fourth sum is $\"3\"$ \r
\n" ); document.write( "\n" ); document.write( " so, the fifth sum must equal $\"9\"$ which is $\"6+%2B+3\"$ \r
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