document.write( "Question 983280: X^3-7x^2-6x+3=0 \n" ); document.write( "

Algebra.Com's Answer #604136 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!
Factorize? Best try synthetic division, as if for checking possible roots. If remainder of 0, then value checked is a root of the equation. When one root found, the two other roots will come from handling the result quadratic expression (the quotient from the first root found).\r
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document.write( "-1    |    1     -7    -6    3\r\n" );
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document.write( "      |          -1     6    0\r\n" );
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document.write( "           1     -6     0     3\r\n" );
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document.write( "+1    |    1     -7    -6    3\r\n" );
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document.write( "      |           1    -6   -12\r\n" );
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document.write( "           1      -6    -12   -9\r\n" );
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document.write( "-3    |    1     -7    -6    3\r\n" );
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document.write( "      |          -3    30    -72\r\n" );
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document.write( "           1     -10   24    -69\r\n" );
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document.write( "+3    |    1     -7    -6    3\r\n" );
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document.write( "      |          3     -12   -54\r\n" );
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document.write( "           1     -4    -18   -51\r\n" );
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\n" ); document.write( "\n" ); document.write( "All the possible RATIONAL roots failed to give remainder of 0.\r
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\n" ); document.write( "\n" ); document.write( "Next method should be some numerical root finding approximation. You might also use a graphing tool. \r
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\n" ); document.write( "\n" ); document.write( "If you are in a hurry (no longer likely), or want to recheck your results, or you believe some roots are complex or irrational, you might try using this:
\n" ); document.write( "http://xrjunque.nom.es/rootfinder.aspx \n" ); document.write( "

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