document.write( "Question 983343: How do I solve this, I'm very confused...
\n" ); document.write( "x^3-3x^2+6x+10=0
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Algebra.Com's Answer #604107 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
Rational Roots Theorem; synthetic division trying roots -1,-2,-5,1,2,5; maybe +10 or -10.\r
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document.write( "-1   |   1   -3   6   10\r\n" );
document.write( "     |       -1   4   -10\r\n" );
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document.write( "         1   -4   10   0 -------- \"highlight%28-1%29\" is a (real) root.\r\n" );
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document.write( "Now use quadratic equation skills to get the two other roots.\r\n" );
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x%2B10=0\"-----comes from the quotient of the previous synthetic division.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%284%2B-+sqrt%2816-4%2A10%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%284%2B-+sqrt%284%284-10%29%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%284%2B-+2sqrt%28-6%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2B-+sqrt%28-6%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x=2%2B-+i%2Asqrt%286%29%29\"-----these are the two complex roots.\r
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\n" ); document.write( "Degree of equation is three; so only three roots.
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