document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=983247>Question 983247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> im getting stuck on this questionss.. thanks..\r<BR>\n" );
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document.write( "Some professional football players seem to earn tremendous amounts of money.  However, their careers professional players are short.  One sports magazine reported that historically the average career length is 4.7 years with a standard deviation of 2.1 years.  A random sample of 50 retired players showed a sample mean career length of 5.5 years.  Construct a hypothesis test to determine whether the average career in professional football is longer than 4.7 years.  Use a 5% level of significance.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #604075 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=604075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First state the null hypothesis(Ho) and the alternative hypothesis(Ha),<BR>\n" );
document.write( "Ho is average career in professional football is longer than 4.7 years<BR>\n" );
document.write( "Ha is average career in professional football is less than or = 4.7 years <BR>\n" );
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document.write( "significance level is 0.05<BR>\n" );
document.write( "the test method will be a 1-tailed test<BR>\n" );
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document.write( "using sample data, we calculate the standard error(SE) of the mean, degrees of freedom(DF), t-score test statistic,<BR>\n" );
document.write( "SE = s / square root(n), where s is the standard deviation of the population and n is the sample size<BR>\n" );
document.write( "SE = 2.1 / square root(50) = 0.296984848<BR>\n" );
document.write( "DF = n - 1 = 50 - 1 = 49<BR>\n" );
document.write( "t = (sample mean - pop mean) / SE = (5.5 - 4.7) / 0.296984848 = 2.69374012<BR>\n" );
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document.write( "we use t-distribution to determine probability(P) of t < 2.69374012, we find<BR>\n" );
document.write( "P( t < 2.69374012) = 0.9952<BR>\n" );
document.write( "This means we would expect to find a sample mean of 5.5 or smaller in 99.5 percent of our samples, if the true population mean were 4.7. Thus the P-value in this analysis is 0.9952<BR>\n" );
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document.write( "Since the P-value (0.9952) is greater than the significance level (0.05), we cannot reject the null hypothesis. </SPAN>\n" );
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