document.write( "Question 967003: The length of a rectangle is 18 cm less than five times its width. Its area is 35 square cm. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #604071 by Timnewman(323) $\"\"$ $\"About$

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from your question,
\n" ); document.write( "L=5w-18-----(1)
\n" ); document.write( "where L=lenght,
\n" ); document.write( " w=width
\n" ); document.write( "but,L*w=35----(2)
\n" ); document.write( "put equ 1 in 2
\n" ); document.write( "(5w-18)w=35
\n" ); document.write( "5w²-18w-35=0
\n" ); document.write( "factorize the quadratic equation and get:
\n" ); document.write( "(5w-7)(w-5)=0
\n" ); document.write( " 5w-7=0 or w-5=0
\n" ); document.write( "5w=7 or w=5cm
\n" ); document.write( "w=7/5cm
\n" ); document.write( "substitute for w in equ 1
\n" ); document.write( "L=5(5)-18
\n" ); document.write( "L=25-18
\n" ); document.write( "L=7cm
\n" ); document.write( "or L=5(7/5)-18
\n" ); document.write( " =7-18
\n" ); document.write( " =-11cm
\n" ); document.write( "now,when w=5cm,L=7cm
\n" ); document.write( "when w=7/5cm,L=11cm \n" ); document.write( "

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