document.write( "Question 983212: A box contains $7.25 in nickels,dimes and quarters. There are 43 coins and the number of quarters is 1 more than three times the number of nickels. Find the number of quarters in the box \n" ); document.write( "
Algebra.Com's Answer #604055 by josgarithmetic(39620)\"\" \"About 
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p n d q for the counts of each coin\r
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\n" ); document.write( "\n" ); document.write( "\"0.01p%2B0.05n%2B0.1d%2B0.25q=7.25\"
\n" ); document.write( "\"p%2B5n%2B10d%2B25q=725\"
\n" ); document.write( "Note that if no pennies, but only nickels, dimes, and quarters, then
\n" ); document.write( "\"5n%2B10d%2B25q=725\"
\n" ); document.write( "\"n%2B2d%2B5q=145\"\r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"p%2Bn%2Bd%2Bq=43\"
\n" ); document.write( "Note that if only nickels, dimes, quarters, then NO pennies.
\n" ); document.write( "\"n%2Bd%2Bq=43\"\r
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\n" ); document.write( "\n" ); document.write( "\"q=1%2B3n\", part of the description. Substitute into the other two simplified equations to eliminate this one variable, q.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28n%2B2d%2B5%283n%2B1%29=145%2Cn%2Bd%2B3n%2B1=43%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28n%2B2d%2B15n%2B5=145%2C4n%2Bd%2B1=43%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%2816n%2B2d=140%2C4n%2Bd=42%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%288n%2Bd=70%2C4n%2Bd=42%29\"
\n" ); document.write( "Use Elimination Method as far as finding either n or d; quicker to eliminate d.
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\n" ); document.write( "\"4n=28\"
\n" ); document.write( "\"highlight%28n=7%29\"-----------------Getting the other two should be no trouble.
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