document.write( "Question 983219: Kindly solve and answer this one for me:\r
\n" ); document.write( "\n" ); document.write( "the sum of an infinite geometric series is 4 while the sum of all the terms is 192. What are the terms?\r
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Algebra.Com's Answer #604044 by ikleyn(52792)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let  a  be the first term of our geometric progression and  r  be its common ratio. \r
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\n" ); document.write( "\n" ); document.write( "Then our first equation is\r
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\n" ); document.write( "\n" ); document.write( "\"a%2F%281-r%29\" = \"4\".\r
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\n" ); document.write( "\n" ); document.write( "It is the formula for the sum of infinite geometric progression.\r
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\n" ); document.write( "\n" ); document.write( "The sequence consisting of cubes of geometric progression is geometric progression itself,  with the first term  \"a%5E3\"  and the common ratio  \"r%5E3\".  It is easy to check. \r
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\n" ); document.write( "\n" ); document.write( "Therefore,  the sum of such progression is \r
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\n" ); document.write( "\n" ); document.write( "\"a%5E3%2F%281-r%5E3%29\" = \"192\".\r
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\n" ); document.write( "\n" ); document.write( "It is our second equation.\r
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\n" ); document.write( "\n" ); document.write( "Now,  divide the second equation by the first one.  You will get\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2F%281%2Br%2Br%5E2%29\" = \"48\".\r
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\n" ); document.write( "\n" ); document.write( "Thus you decreased the degree of the second equation from  3  to  2.\r
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\n" ); document.write( "\n" ); document.write( "Next,  express the term  a  from the first equation as \r
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\n" ); document.write( "\n" ); document.write( "\"a\" = \"4%2A%281-r%29\" \r
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\n" ); document.write( "\n" ); document.write( "and substitute it into the third equation.  You will get \r
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\n" ); document.write( "\n" ); document.write( "\"%284%5E2%2A%281-r%29%5E2%29%2F%281%2Br%2Br%5E2%29\" = \"48\",   or\r
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\n" ); document.write( "\n" ); document.write( "\"%281-r%29%5E2\" = \"3%2A%281%2Br%2Br%5E2%29\",   or\r
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\n" ); document.write( "\n" ); document.write( "\"1+-2r+%2B+r%5E2\" = \"3r%5E2+%2B+3r+%2B3\".\r
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\n" ); document.write( "\n" ); document.write( "It is a quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "Would you solve it and complete the solution from this point?\r
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