document.write( "Question 983230: Find the vertex, focus, directrix, and focal width of the parabola.\r
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document.write( "-1/40 x^2= y \n" );
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Algebra.Com's Answer #604038 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! -1/40 x^2= y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-(1/40)x^2=y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Compare that green outlined equation to the basic form, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A video which explains this well (but a little bit clumsy) is this one: \n" ); document.write( "Equation Derivation for Parabola from Focus and Directrix \n" ); document.write( " |